(1/3)(x+3)^2=5

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Solution for (1/3)(x+3)^2=5 equation: 



(1/3)(x+3)^2=5

We move all terms to the left:

(1/3)(x+3)^2-(5)=0



Domain of the equation: 3)(x+3)^2!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(x+3)^2-5=0

We multiply parentheses ..

(+x^2+1/3*3)^2-5=0

We multiply all the terms by the denominator


(+x^2+1-5*3*3)^2=0

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